Question

write in normal form
A ={ x/x= 2n+1 , where n is the lowest integral factor of 8} ​

Answer 1

Related questions

Express D={x∣x∈I,−3<x≤3} in the roster form:

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Step-by-step explanation:

In roster method , elements of the set are listed within the pair of brackets { } and are separated by commas.

Generally integers {....−2,−1,0,1,2....} are

represented by letter ′I′. Given question is about

integers lying between −3 & 3 including3. So the set D={−2,−1,0,1,2,3}

Answer 2

Given,

A ={ x/x= 2n+1 , where n is the lowest integral factor of 8} ​

So, x is n+1

And n is the lowest integral factor of 8

We know that , lowest integral factor of any number is 1.

Hence, n is 1

So, x = 2(1)+1

=> x = 3

So, A= { 3}