Write in Rosier form
A = { x | x = 2n + 1, NEW, n≤ 5 }
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Given set builder form of a Set is x:x=2n-1 , n in N and n < 6 end gathered
Here, n is natural number less than 6
1,2,3,4,5
Given x = 2n-1
- If n = 1 then x = 2×1 - 1 = 2-1 = 1
- If n = 2 then x = 2×2 - 1 = 4-1 = 3
- If n = 3 then x = 2×3 - 1 = 6-1 = 5
- If n = 4 then x = 2×4 - 1 = 8-1 = 7
- If n = 5 then x = 2×5 - 1 = 10-1 = 9
Hope this helps !
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