Math, asked by swethasatheesh3, 5 months ago

write in set builder form A = {14,23,32,41,50}

Answers

Answered by nidhigupta09
21

Answer:

A = {x|x=n+9,n€N,n=41}

Answered by talasilavijaya
0

Answer:

In set builder form, A= \big\{ x:x=n+9, n\in N, 14 \leq n \leq 50 \big\}

Step-by-step explanation:

Given A= \big\{ 14, 23, 32, 41,50 \big\}

  • In the given set, 9 is added to the number to the next number, so it can be written as x=n+9
  • And the set of natural numbers is given, so n \in N
  • And the value of x is in between 14 and 50, so 14 < x < 50

Writing in set builder form,

                      A= \big\{ x:x=n+9, n\in N, 14 \leq n \leq 50 \big\}

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