Question

Write in the expanded form: (3a-2b-3c)²
Please help me..​

Answer 1

Answer:

(3a-2b)³=(3a)³-(2b)³-3(3a)(2b)[(3a)-(2b)]

(3a-2b)³=27a³-8b³-18ab(3a-2b)

(3a-2b)³=27a³-8b³-54a²b+36ab²(ANSWER)

Since (a-b)³=a³+b³-3ab(a-b)

Answer 2

Answer:

applying the formula of (a-b-c)2

(a-b-c)2=a2 +b2 +c2 -2(ab-bc+ca)

so,3a2+2b2+3c2-2(3a×2b -2b×3c+3c×3a)

:- 9a2+4b2+9c2-2(6ab-6bc+9ca)

9a2+4b2+9c2-12ab+6bc-18ca Ans