write in the form of a+ib z=2+i/(1+i)(1-2i)
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Step-by-step explanation:
z=2+i/(1+i)(1-2i)
=2+i/1-2i+i-2i²
=2+i/3-i
=2+i/3-i×3+i/3+i
=6+2i+3i-1/9-i²
=5+5i/10
=1+i/2
=1/2+i.1/2
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