Question

write in the standatd form of 3x+2x^3-√2x^6-7

Answer 1

$3x + {2x}^{3} - \sqrt{2} {x}^{6} - 7 = 0 \\ - \sqrt{2} {x}^{6} + 2 {x}^{3} + 3x - 7 = 0 \\ \sqrt{2} {x}^{6} - 2 {x}^{3} - 3x + 7 = 0 \\ \sqrt{2} {x}^{6} + {0x}^{5} + {0x}^{4} - 2 {x}^{ 3} - {0x}^{2} - 3x + 7 = 0$
is the standard form