Write lengths of “Hypotenuse”, “Opposite side” and “Adjacent side” for the given angles in the given triangles.
1. For angle C
2. For angle A
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Answered by
55
AB= (√AC^2-BC^2). [by Pythagoras theorem]
=√5^2-4^2
=√25-16
=√9= 3
AB=3cm
For angle C
hypotenuse= 5cm
opposite side= AB= 3cm
adjacent side=BC= 4cm
For angle A
hypotenuse= 5cm
opposite side= BC= 4cm
adjacent side= AB= 3cm
=√5^2-4^2
=√25-16
=√9= 3
AB=3cm
For angle C
hypotenuse= 5cm
opposite side= AB= 3cm
adjacent side=BC= 4cm
For angle A
hypotenuse= 5cm
opposite side= BC= 4cm
adjacent side= AB= 3cm
Answered by
22
For angle C
Hypo - Ac - 5 cm
Perpendicular -BA
Base - BC -4 CM
FOR ANGLE A
HYPO--- AC
PERPENDICULAR---- BC
BASE--- AB
AB= (√AC^2-BC^2). ( Pythagoras theorem)
=√5^2-4^2
=√25-16
=√9= 3
AB=3cm
I HOPE THAT HELP U!
Hypo - Ac - 5 cm
Perpendicular -BA
Base - BC -4 CM
FOR ANGLE A
HYPO--- AC
PERPENDICULAR---- BC
BASE--- AB
AB= (√AC^2-BC^2). ( Pythagoras theorem)
=√5^2-4^2
=√25-16
=√9= 3
AB=3cm
I HOPE THAT HELP U!
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