Question

write linear equation such that each point on its graph has an ordinate one more than 3.5 times it's abcissa

Answer 1

Hey mate!

It is given that, the ordinate of the point is one more than 3.5 times its abcissa. So,

y = 1+3.5x

That's the answer!

Hope it helps :)

Answer 2

Let the abscissa of the point be x,
According to the question, Ordinate (y) = 3 x Abscissa ⇒ y=3x When x = 1, then y = 3 x 1 = 3 and when x = 2, then y = 3 x 2 = 6.

Here, we find two points A (1,3) and B (2, 6). So, draw the graph by plotting the points and joining the line AB.

Hence, y = 3x is the required equation such that each point on its graph has an ordinate 3 times its abscissa.