English, asked by djdurgarao3, 10 months ago

write log 16 - laga intro single
logarithm

Answers

Answered by sivanigundavarapu

0

Answer:

log(16/a)

Explanation:

log16-loga

=w.k.t loga-logb=log(a/b)

so,log16-loga=log(16/a)

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