write log64/729in its expansion form
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Answered by
1
log 64/729 = log 64 - log 729
= log 2^6 - log 3^6
= 6log2 - 6log3
= 6 ( log2 - log3 )
HOPE IT HELPS....
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Answered by
1
log64/729=log2^6/3^6=6log(2/3)
so, the expansion form is 6log(2/3).
please mark as brainliest
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