Question

Write mathematical Form of 3rd equation of motion.​

Answer 1

Answer:

Let us assume a body that has a mass “m” and initial velocity “u”. Let after time “t” its final velocity becomes “v” due to uniform acceleration “a”. Now we know that:

Acceleration = Change in velocity/Time Taken

Therefore,  Acceleration = (Final Velocity-Initial Velocity) / Time Taken

Hence, a = v-u /t or at = v-u

Therefore, we have: v = u + at

v² = u² + 2as

We have, v = u + at. Hence, we can write t = (v-u)/a

Also, we know that, Distance = average velocity × Time

Therefore, for constant acceleration we can write: Average velocity = (final velocity + initial velocty)/2 = (v+u)/2

Hence, Distance (s) = [(v+u)/2]  × [(v-u)/a]

or  s = (v² – u²)/2a

or 2as = v² – u²

or v² = u² + 2as

Answer 2

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$\large{ \mathrm{ \bullet{ mathematical\: form \: of \: 3rd \: law \: of }}}$$\large{ \mathrm{ motion }}$

$\huge{ \mathrm{ \underline{ \green{Answer}}}}$

$\huge{ \boxed{ \pink{ \mathrm{ \ v^2 - \ u^2 = 2aS}}}}$

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$\huge{@itzBrainlyTanuj}$