Question

write molecular optical configuration of neon 2 molecules. also show that ne2 molecules does not exist
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Answer 1

$\textsf{\Large {\underline {Chemical Bonding and Molecular Structure}}}$ :

Electronic configuration of Neon, $\mathsf{Ne_2}$ = $\mathsf{{({\sigma}\:1s)} ^{2}}$ $\mathsf{{({\sigma} ^{*} \:1s)} ^{2}}$ $\mathsf{{({ \sigma}\:2s)} ^{2}}$ $\mathsf{{({\sigma} ^{*} \:2s)} ^{2}}$ $\mathsf{{({ \sigma}\:2p_z)} ^{2}}$$\mathsf{{({ \pi}\:2p_x)} ^{2}}$$\mathsf{{({ \pi}\:2p_y)} ^{2}}$$\mathsf{{({\pi} ^{*} \:2p_x)} ^{2}}$$\mathsf{{({\pi} ^{*} \:2p_y)} ^{2}}$$\mathsf{{({\sigma} ^{*} \:2p_z)} ^{2}}$

Now, we will find the Bond Order of $\mathsf{Ne_2}$.

$\boxed{\mathsf{B. O. \:=\:{\dfrac{Electrons\: in \:B. M. O. \:-\:Electrons \:in\:A. B. M. O.} {2}}}}$

⚫B. M. O. = Bonding Molecular Orbital.

⚫A. B. M. O. =Anti - Bonding Molecular Orbital.

Bond Order = $\mathsf{\dfrac {8\:-\:8}{2}}$

➡️ Bond Order = 0

Hence, $\mathsf{Ne_2}$ molecule does not exist because it's bond order is 0.

Answer 2

Answer:

bond order =0

neon does not exist