Write movement of inertia of solid sphere about an axis passing through diameter
Answers
Answer:
0.4 MR^2 is the answer precisely speaking. It can be derived using a long integration taking an elementary object as disc.i will edit my answer and add it if you really need it.
However, if you are preparing for the competitive examination then the formula itself is enough but for conceptual clarity, the derivation must be understood.you can easily find it in any plus two books and for that matter any class notes.
However, if you really need it then please do comment and I shall surely edit my answer and add it
Moment of inertia of a solid sphere about diameter=0.4MR^2 where M is mass and R is radius
PS: this is only for constant mass distribution for variable mass distribution you have no choice but to follow the proper integration process using an elementary disc.
Explanation:
hope this helps you
Answer:
Hence, movement of inertia of solid sphere about an axis passing through diameter = 0.4 mr^2
Explanation:
The moment of inertia is the reluctance to change the state of motion (rotation) of an object rotating around a given axis
Therefore, the moment of inertia of a solid sphere about its diameter (axis) is expressed as follows;
I=(2/5)*m*r^2
Where;
m-mass of the solid sphere
r -radius of the sphere
=> I = 0.4 mr^2
Hence, movement of inertia of solid sphere about an axis passing through diameter = 0.4 mr^2