Question

write
nature
of roots of 3x² + x + 8.​

Answer 1

Answer:

$3 {x}^{2} + x + 8 = 0$

• comparing the equation with

$a {x}^{2} + bx + c = 0$

we get,

a=3

b=1

c=8

• the discriminant of the equation

$= \sqrt{ {b}^{2} - 4ac} \\ = \sqrt{ {1}^{2} - 4 \times 3 \times 8 } \\ = \sqrt{1 - 96} \\ = \sqrt{ - 95}$

here,

the number √(-95) is an unreal number

so, the roots of the equation will also be unreal