Question

write Nernst equation for a Daniel cell (assume activity of metals is unity).​

Answer 1

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HERE IS YOUR ANSWER,

Nernst’s Equation for Daniells Cell

Daniell’s cell consists of zinc and copper electrodes. The electrode reactions in Daniell’s cell are,

At anode :  Zn(s) ---->Zn3+ (aq)+2e--

At cathode :  Cu3+(aq)+2e--  ---->Cu(s)

Net cell reaction :  Zn(s)+Cu3+(aq)---->Cu(s)+Zn3+(aq)

Therefore, the Nernst equation for the Daniell’s cell is,

Ee(pie)=E0e(pie)---2.303 RT   log [Cu(s)] [Zn3+(aq)]

                                2 F                [Zn(s)] [Cu3+(aq)]

Since, the activities of pure copper and zinc metals are taken as unity, hence the Nernst equation for the Daniell’s cell is,

Ee(pie)=E0e (pie)---2.303 RT log [Zn3+(aq)]

                                  2  F               [ Cu3+(aq)]

 

The above eq. at 298 K is,

Ee(pie)=E0e(pie)---0.0591 log [Zn3+(aq)]    V

                                 2              [ Cu3+(aq)]

For Daniells cell, E0e(pie)=1.1 V

NOTE;----THERE WAS NO SYMBOL PIE IN MY KEYBOARD...

                UNDERSTAND(PIE)

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