Question

Write Nernst equation for the following Electro chemical cell and calculate the cell
potential of it.
Ni(s) / Ni+2 (aq) (i) Ag+ (aq)/Ag (s)
0.01 M 0.1 M .
E°Ni+2/Ni=-0.25V EºAg/ = +0.80 V​

Answer 1

Answer:

Nerst equation: E=E0-(0.0529/n)log(red/oxdation)

Explanation:

E0=Ecathode-Eanode0

   =0.8+0.25

   =1.05V

reaction equation:2Ag++Ni--------2Ag +Ni2+

E=1.05-0.0529/2log(0.1)^2/0.01

E=1.05-0

E=1.05V

Cheers!