Question

Write next four terms of the A.P., whose first term is 12 and common difference is 2.

Answer 1

Answer:

14,16,18,20

Step-by-step explanation:

Tn= a+ (n-1)d

where a=first term

d=common difference

Tn= nth term

by putting a=12

d = 2

and

n=1,2,3,4

we can get the Answers.

Answer 2

Answer:

t1=12, t2=14, t3=16, t4=18, t5=20

Step-by-step explanation:

$given \: a = 12 \: and \: d = 2 \\ \\ the \: nth \: term \: of \: an \: a.p. \: with \: given \: first \: term \: and \: common \: difference \: is \: given \: by \: \\ a + (n - 1)d \\ \\ t1 = a = 12 \\ t2 = a + d = 12 + 2 = 14 \\ t3 = a + 2d = 12 + 2.2 \\ = 12 + 4= 16\\ t4 = a + 3d = 12 + 3.2 \\ = 12 + 6 = 18 \\ t5 = a + 4d = 12 + 4.2 \\ = 12 + 8 = 20$

Hope it helps

Thank you.........

❤❤❤❤❤❤❤