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refer the attachment for your answer.
hope it helps you
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Answer:
2 FeCl3 + 2 HI → 2 FeCl2 + I2 + 2 HCl
This is an oxidation-reduction (redox) reaction:
2 I-I - 2 e- → 2 I0 (oxidation)
2 FeIII + 2 e- → 2 FeII (reduction)
HI is a reducing agent, FeCl3 is an oxidizing agent.
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