Chemistry, asked by Rahane27, 1 year ago

Write notes on Fridel Craft’s alkylation.

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Answered by shubham639
1
Friedel–Crafts alkylation involves thealkylation of an aromatic ring with an alkyl halide using a strong Lewis acid catalyst. With anhydrous ferric chloride as a catalyst, the alkyl group attaches at the former site of the chloride ion. The general mechanism is shown below.

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Answered by Anonymous
1
Friedel–Crafts alkylation.Friedel–Crafts alkylation involves the alkylation of an aromatic ring with an alkyl halide using a strong Lewis acid catalyst. With anhydrous ferric chloride as a catalyst, the alkyl group attaches at the former site of the chloride ion.
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