Computer Science, asked by shaurya2078, 4 months ago

Write of length program and to check whether the number is

Armstrong or not. ​

Answers

Answered by 7702029397
2

Answer:

positive integer is called an Armstrong number of order n if

abcd... = an + bn + cn + dn + ...

In case of an Armstrong number of 3 digits, the sum of cubes of each digits is equal to the number itself. For example:

153 = 1*1*1 + 5*5*5 + 3*3*3 // 153 is an Armstrong number.

Example 1: Check Armstrong Number for 3 digit number

public class Armstrong {

public static void main(String[] args) {

int number = 371, originalNumber, remainder, result = 0;

originalNumber = number;

while (originalNumber != 0)

{

remainder = originalNumber % 10;

result += Math.pow(remainder, 3);

originalNumber /= 10;

}

if(result == number)

System.out.println(number + " is an Armstrong number.");

else

System.out.println(number + " is not an Armstrong number.");

}

}

Answered by TheUntrustworthy
0

An Armstrong number is a number whose sum of cubes of digits is equal to the number itself.

For example:

153 = 1³+5³+3³

1+125+27

=153

Program:

import java. util.*;

class Armstrong

{

public static void main (string args [])

{

Scanner sc = new Scanner

int n, r, p, s=0, m;

System.out.println ("Enter a number");

n=sc.nextInt();

while

{

r=n%10

p=r*r*r;

s=s+p;

n=n/10;

}

if (m==s)

System.out.println (m+"is Armstrong");

else

System.out.println (m+"is not Armstrong");

}

}

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