write one equation to explain esterification and saponification
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Esterification-
When alcohol and ethanoic acid are treated with an acid, ester is formed.
CH3CH2OH + CH3COOH
Acid
--------> CH3COOC2H5
Saponification-
When ester us treated with a base, it gives back alcohol and a salt of carboxylic acid.
CH3COOC2H5
NaOH
-----------> CH3COONA + C2H5OH
When alcohol and ethanoic acid are treated with an acid, ester is formed.
CH3CH2OH + CH3COOH
Acid
--------> CH3COOC2H5
Saponification-
When ester us treated with a base, it gives back alcohol and a salt of carboxylic acid.
CH3COOC2H5
NaOH
-----------> CH3COONA + C2H5OH
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