Question

write one solution of each of the following equations (a) 4x-3y=0 (b) 2y-y=3

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Answer 1

Answer:

(a) let x be 1.

A.T.Q

4x-3y=0

4(1)-3y=0

4-3y=0

-3y= (-4)

y = -4/-3

y = 4/3

(b) 2y-y = 3

y = 3

Answer 2

Answer:

a) we can assume x to be 1.

substituting the value of x,

4(1) - 3y=0

4-3y=0

4=0+3y (bringing 3 to the RHS)

4=3y

therefore,

y=4/3

b) 2y-y=3

here we can subtract the term "2y-y" since it is a like term.

On subtracting we get,

y=3.

this is the answer.