Write one solution of each of the following equations
(a) 4x – 3y = 0
(b) 2x – y = 3
Answers
Answered by
37
HEY BUDDY..!!
HERE'S THE ANSWER..
____________________
( a ) 4 x – 3 y = 0
=> 4 x = 3 y
⏺️ If y = 4 then x = 3
( b ) 2 x – y = 3
=> 2 x = y + 3
⏺️ If y = 1 then x = 2
HOPE HELPED..
GOOD EVENING..
:-)
HERE'S THE ANSWER..
____________________
( a ) 4 x – 3 y = 0
=> 4 x = 3 y
⏺️ If y = 4 then x = 3
( b ) 2 x – y = 3
=> 2 x = y + 3
⏺️ If y = 1 then x = 2
HOPE HELPED..
GOOD EVENING..
:-)
sakshig:
Ops ;-) very good
Answered by
24
Please don't report my answer because i m confused if these 2 equations are of same question then by substitution method
4x-3y=0
4x=3y
X=3y/4 -c
Put equation c in equation b
2x-y=3
X=3y/4
2×3y/4-y=3
3y/2-y=3
By taking lcm of denominator
3y/2-2y/2=3
y/2=3
y=3×2
y=6 -d
Put d in a
4x - 3y =0
4x-3×6=0
4x-18=0
4x=18
x=18/4
PLEASE MARK ME BRAINLIEST
4x-3y=0
4x=3y
X=3y/4 -c
Put equation c in equation b
2x-y=3
X=3y/4
2×3y/4-y=3
3y/2-y=3
By taking lcm of denominator
3y/2-2y/2=3
y/2=3
y=3×2
y=6 -d
Put d in a
4x - 3y =0
4x-3×6=0
4x-18=0
4x=18
x=18/4
PLEASE MARK ME BRAINLIEST
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