Question

write oxhidation number of P in NaH2Po2​

Answer 1

Answer:

Let oxidation state(os)of  P is NaH2PO2 be x

os of oxygen is -2

os of Na is +1

os of hydrogen is +1

Total os of a molecule is zero (if neutral).

so by adding  os we get

(+1)+(+1×2)+(x)+-2×2)=0

or

x=+1

So oxidation state of phosphorus in NaH2PO2 is +1