Question

write oxidation state of chromium and cobalt in this two compounds​

Answer 1

I) Let, x be the oxidation number of Cr in [Cr(NH3)6]

Now,

x+6×(0)+3×(−1)=0

x−3=0 ⇒x=+3.

Oxidation number of Cr is =+3

ii) Let x be the oxidation state of Co in [Co(CN)6].

Since the overall charge on the complex is −3, the sum of oxidation states of all elements in it should be equal to −3.

Therefore, x+6(−1)=−3

or, x=+3.

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