write p/q form of 0.3bar
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Answered by
21
let x = 0.333333... (1)
10x =3.333333...(2)
subtracting (1) from (2)
9x =3.o
x= 1/3= o.3333333
10x =3.333333...(2)
subtracting (1) from (2)
9x =3.o
x= 1/3= o.3333333
Answered by
17
Hello friend.....☺
Here is your solution......☺
♦ Let x = 0.333 ----------(1)
=> 10x = 3.333 ---------(2)
⭐ On subtracting eq(1) from (2) we get,
=> 10x -x = 3
=> 9x = 3
=> x = 3/9
=> x = 1/3
Hence, p/q form of 0.333...... is 1/3.
Thanks....☺
Hope this helps you....☺
Here is your solution......☺
♦ Let x = 0.333 ----------(1)
=> 10x = 3.333 ---------(2)
⭐ On subtracting eq(1) from (2) we get,
=> 10x -x = 3
=> 9x = 3
=> x = 3/9
=> x = 1/3
Hence, p/q form of 0.333...... is 1/3.
Thanks....☺
Hope this helps you....☺
Hence, x = 0.33333333…. - eqn (a)
Now, 10x = 3.33333333….. -eqn (b)
Hence, taking eqn(b) - eqn(a); we have
9x = 3
Hence, x = 1/3.
Similar questions
Hence, x = 0.33333333…. - eqn (a)
Now, 10x = 3.33333333….. -eqn (b)
Hence, taking eqn(b) - eqn(a); we have
9x = 3
Hence, x = 1/3.