Question

write please.........​

Answer 1

answer of 23 is 3.it is prepared by contact process

Answer 2

Explanation:

23) Which of the following statement is incorrect about sulphuric acid -

a) In water it mainly ionises in 1st step

b) B.P. is high due to strong H-bond

c) It is prepared by contact process

d) Because of high votality it's used to prepare other acids. ✔

Explanation :-

1. Sulphuric acid is a dibasic acid. In aqueous solution it ionises in two steps, but it mainly ionises in 1st step.
2. Sulphuric acid boils at 611 K and freeze at 283 K. Boiling point is high because of strong intermolecular H-bonds.
3. Sulphuric acid is manufactured by contact process.
4. Sulphuric acid is low votality. Due to its low votlality, it is used to manufacture more volatile acids.

24) In which of the following nitrogen undergoes oxidation ?

a) N2 to NH3

b) N2O4 to NO2

c) NO3- to N2O5

d) NO2- to NO3- ✔

Explaination :-

Let's Check all option and see that which is reducing and which one is oxidising.

Option a)

O.N. of N2 is 0 & NH3 is -3.

Calculation :-

NH3 :-

x + 1×3 = 0

x = -3

Hence, O.N. is decreasing. It means, Reduction.

Option b)

O.N. of N2O4 & NO2 is +4

Calculation :-

N2O4 :-

2x - 2×4 = 0

2x = 8

x = 4

And

NO2 :-

x -2×2 = 0

x = 4

Hence,

O.N. is neither decreasing nor increasing. It means, Not reduction nor oxidation.

Not reduction nor oxidation. Option c)

O.N. of NO3- & N2O5 is +5

Calculation :-

NO3- :-

x - 2×3 = -1

x = 6 - 1

x = 5

And

N2O5 :-

2x - 2×5 = 0

2x = 10

x = 5

Hence,

O.N. is neither decreasing nor increasing. It means, Not reduction nor oxidation.

Not reduction nor oxidation. Option d)

O.N. of NO2- is

Calculation :-

NO2- :-

x - 2×2 = -1

x = 4 - 1

x = 3

And

NO3- :-

x - 2×3 = -1

x = 6 - 1

x = 5

Hence,

O.N. is increasing from 3 to 5.

It means, Oxidation.

Therefore,

Option D is correct.