Write plynomial if zeros are (3+root2) and (3-root 2)
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Answer:let alpha be 3 + root 2 and let beta be 3 - root 2.
Step-by-step explanation:
Hence .......
Alpha + beta = -b÷a
So
(3-root2)+(3+root2)= -b÷a
3+3÷1= -b÷a
Hence .....
B= -6 and A= 1
Now .
Alpha × beta = C÷A
So.
Putting values of alpha and beta:-
(3+root2)×(3-root2)=C÷A
{Using identity:-(a-b)×(a+b)=a×a-b×b}
3×3-root2×root2÷1=C÷A
6-2÷1=C÷A
4÷1=C÷A
Hence.....C=4
Therefore the polynomial will be:-
X × X +(-6)X + 4 = 0
=> ..............X×X - 6X +4 = 0 ....................
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