Question

write polynomial in standard form whoes coefficient form is ( 1,,2,3)​

Answer 1

1) 6y3+4y5-2y2-6y+8y4+7

The highest exponent is the 5, so that entire term must be written first:4y5

The next highest exponent is the 4 so that term comes next. So far we have 4y5+8y4

The next highest exponent is the 3 so add that term to get

4y5 +8y4+6y3

Then comes 2. Notice that this term is negative, so don't forget to include the negative sign:

4y5 +8y4 +6y3-2y2

Remember that term has an understood exponent of 1 so it comes next. 4y5+8y4+6y3-2y2 -6y

The constant term (a number with no variable) always comes last so the final answer is:

4y5+8y4+6y3-2y2-6y+7

2) 9y2+5y-3y8

Often, the polynomial does not contain all of the exponents. You still follow the same procedure listing the highest exponent first (8) then the next (2) and finally the term with just a variable (understood exponent of 1). Notice that the negative sign stayed with the three)

Answer: -3y8+9y2+5y