Question

Write program that reads an integer N from keyboard computes and display the sum of number from N to (2*N) if N is non-negative.If N is negative number, the it's sum of the number (2*N) to N. The starting and ending point are included in the sum.

Answer 1

Answer:

mark as branlist

this works completely in c language

*********************

#include <conio.h>;

#include <stdio.h>;

void main ()

{

int n,x;

clrscr ();

printf ("enter number to multiply /n");

scanf ("%d",&n);

x=n*2;

printf (answer= );

printf ("%d",x);

}

Answer 2

Answer:

N=int(input("Enter the value of N:"))

summ=0

if N<0:

   for i in range(N*2,N+1):

       summ+=i

   print("Sum of the numbers from (N*2) to N is:",summ)

else:

   for i in range(N,(N*2)+1):

       summ+=i

   print("Sum of the numbers from N to (N*2) is:",summ)

Explanation: