write programming in C language to find the leap years
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#include <stdio.h> int main() { int year; printf("Enter a year: "); scanf("%d",&year); if(year%4 == 0) { if( year%100 == 0) { // year is divisible by 400, hence the year is a leap year if ( year%400 == 0) printf("%d is a leap year.", year); else printf("%d is not a leap year.", year); } else printf("%d is a leap year.", year ); } else printf("%d is not a leap year.", year); return 0; }
Output 1
Enter a year: 1900 1900 is not a leap year.
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Output 1
Enter a year: 1900 1900 is not a leap year.
I hope this helps you .
mark me as Brainlist .
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Answer:
Leap Year Program In C
It is evenly divisible by 100. If it is divisible by 100, then it should also be divisible by 400.
Except this, all other years evenly divisible by 4 are leap years.
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