Write Pythagorean triplet whose one member is 16.
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Therefore, the triplets are 16, 63 and 65. Hence, the Pythagorean triplet whose one member is 16 is 16, 63 and 65.
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Answer:
Let 2m be 16
Now, 2m = m^2 + 1, m^2 - 1
If 2m = 16
m = 16/2 = 8
Now,
m^2 + 1 = 8^2 + 1 = 64 + 1 = 65
m^2 - 1 = 8^2 - 1 = 64 - 1 = 63
Therefore, Pythagorean triplet of 16 = 16,63,65
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