write Pythagorean triplet whose one member is 6
Answers
Answered by
34
Let 2m = 3
m= 3
Therefore,
m^2 +1= 9+1 = 10
m^2 -1= 9-1 = 8
The triplet = 6,8,10
m= 3
Therefore,
m^2 +1= 9+1 = 10
m^2 -1= 9-1 = 8
The triplet = 6,8,10
Khushi10on10:
please mark it as brainliest
Similar questions