Math, asked by hariprasanthrk, 3 months ago

Write Pythagorean triplet whose smallest member is 8

Answers

Answered by roma0613

5

Answer:

It is given that smallest number is 8. So, 2m = 8. Now, second number = m² -1 = 4² – 1 = 15 and, third number = m² + 1 = 4² + 1 = 17. Hence, the triplet is 8, 15 and 17.

Answered by jasvindarsinghkuttan

1

Answer:

8, 15 and 17.

Step-by-step explanation:

It is given that smallest number is 8. So, 2m = 8. Now, second number = m² -1 = 4² – 1 = 15 and, third number = m² + 1 = 4² + 1 = 17. Hence, the triplet is 8, 15 and 17.

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