Question

Write python code for following pattern ,

Answer 1

Answer:

Input:

i = 1

j = 6

for row in range (0, 7) :

for col in range (0, 7) :

if row == 0 or row == 6 :

print ( "#", end = " " )

elif now == I and == j :

print ( "#", end = " " )

i = i + 1

j = j - 1

else:

print ( end = " " )

print ( )

Output:

(Firstly it shows the information of your desktop, some information like time, data, etc..)

>>>

================RESTART: C:\user\username\Desktop\pattern.py=

# # # # # # #

#

#

#

#

#

# # # # # # #

>>>

That's the end of the output and the codings. The concept of python is very easy!

Refer the attachment for the processing python diagram for this this pattern.

Thank you ;)

Answer 2

# Interesting program!

# I will start with the 2nd as it'll be easy to understand.

1. The Z

1. # Let's print "#" in a line for the Top of the "Z"
2. # I'll be using the for loop.
3. for i in range(7):   # This will start the loop from 0-7.
4.    print("#", end = ' ')  
5. print()
6. # Now Let's go for the diagonal
7. for i in range(6,1,-1):  
8.    for j in range(2 * (7 - i)):
9.        print(' ', end = '')  # I'm printing this line for making the alignment for the diagonal  
10.    print("#", end = '') # This line will print the "#" in one line but due to the above line it'll get printed in diagonal line.
11.    print()
12. # Like the top line, I'll be printing the bottom line.
13. for i in range(7):  
14.    print("#", end = ' ')  

2. The Reverse Z

1. # The Code will be same. We will just change the index value of the for loop in the diagonal.
2. for i in range(7):  
3.    print("#", end = ' ')  
4. print()  
5. for i in range(1, 6):   # Just see the index value.
6.    for j in range(2 * (7 - i - 1)):  
7.        print(' ', end = '')  
8.    print("#", end = '')  
9.    print()  
10. for i in range(7):  
11.    print("#", end = ' ')