Question

write python recursive code to computer and print sum of square of n number. value of n is passed as parameter.

Answer 1

Answer:

def sum(n):

 if(n==0):

   return 0

 else:

   return (n*n)+sum(n-1)

a=sum(int(input()))

print(a)

Explanation:

Answer 2

Python recursive code to print the sum of the square of n number.

def square_sum (num):

   if num == 1:

       return 1

   else:

       return num * num + square_sum (num-1)

num = int (input ("Enter the number: "))

print ("The sum of square of the entered number is: ", square_sum (num))

In the above program, "num" is the input number passed as a parameter.

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