Question

write quadratic polynomial , sum of whose zeroes is 2 and product is -8 answer
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Answer 1

$sum \: of \: zeros = 2$

$product \: of \: zeros = - 8$

${f(x) = k( {x}^{2} - (2)x + ( - 8)}$

$f(x) = k( {x}^{2} - 2x - 8)$

$is \: your \: answer$

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Answer 2

$\huge\mathfrak\pink{❦︎Answer❦︎}$

Let α and β are the roots of given Quadratic polynomial.

Sum of zeroes ( α+β ) = 2

Product of zeroes ( αβ ) = -8

$\mathbb\blue{Formula}$

$\mathbb\green{x²−(α+β)x+(αβ)}$

===> x² - (2)x + (-8)

===> x² -2x -8

So,

$\huge\mathfrak\red{x²-2x-8}$