Question

Write quadratic polynomial whose one zero is 3-√5 and product of zeroes is 4.Give full explanation please.. I will mark the person as brainiest who gives the answer first with full explanation...​

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer:

${x}^{2} - 6x + 4$

Step-by-step explanation:

$let \: the \: zeroes \: of \: the \: polynomial \\ \: p(x)be \: \alpha \: and \: \beta$

$\alpha = 3 - \sqrt{5} \\ \alpha \times \beta = 4 \\ (3 - \sqrt{5} ) \times \beta = 4 \\ \beta = \frac{4}{3 - \sqrt{5} } \times \frac{3 + \sqrt{5} }{3 + \sqrt{5} } \\ \beta = \frac{4(3 - \sqrt{5} )}{9 - 5}$

$\beta = \frac{4(3 + \sqrt{5} )}{4} \\ \beta = 3 + \sqrt{5} \\ \alpha + \beta = 3 - \sqrt{5} + 3 + \sqrt{5} \\ = 6$

$p(x) = {x}^{2} - ( \alpha + \beta )x + \alpha \beta \\ p(x) = {x}^{2} - 6x + 4$

plz mark as brainlist