Question

write quadratic polynomial whose sum and product are 3/5 and-1/2 respectively

Answer 1

Answer:X+y=underroot 2--eq1

And x*y=3

x=3/y

Now put value in eq 1

3/y+y=√2

3+y2÷y =√2

So 3+y2=√2y

Hence we get an quadratic eq

y^2-√2y+3=0

Now solve it and get value of y and then put the value of y in eq 1 from there you get value of x

Step-by-step explanation:

Answer 2

Answer:

10x^2 - 6x - 5

Step-by-step explanation:

Formula for quadratic equation is k[x^2 - (alpha+beta)x alpha.beta]

                                                     = k[x^2 - 3/5x + (-1/2)]

                                                     =x^2 - 3/5x - 1/2

                                   On taking LCM we get

                                           10x^2 - 6x - 5