Question

write quadratic polynomial whose zeroes of the solution of x+y=7 and x-y=3​

Answer 1

Answer:

x+y=7

+x-y=3

______

2x=10

x=5

y=2

quadratic eqn is a square_(5+2)a+5(2)

=>a square-7a+10

Answer 2

The quadratic equation is $a^{2}$ - 7 a +10

Given

To find the quadratic polynomial.

x + y = 7  ----> ( 1 )

x - y = 3  ----> ( 2)

Solving the equation ( 1 ) and equation ( 2) we get,

                          x +  y = 7

                          x -  y  = 3

    Answer =>  2x + 0y = 10

         Hence,   2x = 10

                          x = $\frac{10}{2}$ = 5

                          x = 5

Now, substitute x=5 value in equation ( 1 ) or equation ( 2 )

Solving x=5 in equation ( 1 ), we get

                            x + y = 7   ( x = 5 )

                            5 + y = 7

                            y = 7 - 5 = 2

                            y = 2

Quadratic equation is a^2 - ( x + y ) a + ( x . y)

                                    $a^{2}$ - ( 5 + 2 ) a + ( 5 × 2 )

                                   $a^{2}$ - 7 a + 10

To learn more...

write quadratic polynomial whose zeroes of the solution of x+y=7 and x-y=3​

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