Question

Write Rationalising factor for 6\√12-√3​

Answer 1

Answer:

root12 plus root5 is its rationalising factor

Answer 2

$\frac{6}{ \sqrt{12} - \sqrt{3} } \times \frac{ \sqrt{12} + \sqrt{3} }{ \sqrt{12} + \sqrt{3} }$

$\frac{6 \sqrt{12} + 6 \sqrt{3} }{12 - 3}$

$\frac{12 \sqrt{3} + 6 \sqrt{3} }{9}$

$\frac{18 \sqrt{3} }{9}$

$2 \sqrt{3}$

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