Physics, asked by ishasaswade414, 10 months ago

write relation for power drawn in three phase star connection load

Answers

Answered by manojatindia
1

Answer:

Power in three phase circuit is given by

√3×line voltage×line current

In star connected load, line voltage is sqrt(3) of phase voltage and line current is same as phase current.

Delta connected load, it is opposite to star connection that is, phase voltage = line voltage, line current = √3×phase current

So power in each phase = phase voltage × line current.

Power in each phase in star connected load

= (Line voltage/√3) × line current

In Delta connected load = line voltage × line current/√3

Power in each phase so in all three phases is equal in both cases of star and delta connection.

Let understand this problem from further prospective, if equal resistance R are connected in star and then delta from supply of line voltage V

Star connection: phase voltage = V/√3

Phase current = phase voltage/R = V/√3 R

Star connection line current = phase current = V/√3 R

So total power = √3 x V x V/√3 R = V^2/R

Delta connection: line voltage = phase voltage = V

Phase current = phase voltage/R = V/R

Power consumption = √3 line voltage x line current = √3 V x V/R = √3V^2/R

Ratio of power in delta to star connected resistance R = √3.

Contradictory results from both statement

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Answered by gavhadvr03
1

Answer:

In star connected load, line voltage is sqrt(3) of phase voltage and line current is same as phase current. So power in each phase = phase voltage × line current. Power in each phase so in all three phases is equal in both cases of star and delta connection. Ratio of power in delta to star connected resistance R = √3.

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