Write rhe cubic polynomial whose zeroes are 6,10,4
Answers
Answered by
11
Heya.
Your answer is here....
Given zeroes are :- 6, 10, and 4.
Sum of the zeroes = α+β+γ
= 6 + 10 + 4 = 20
Sum of the product of the zeroes taken two at a time = αβ+βγ+αγ
= 6 X 10 + 10 X 4 + 4 X 6 = 60 + 40 + 24 = 124
Product of zeroes = αβγ
= 6 X 10 X 4 = 240.
Using the cubic formula,
x³ - ( α+β+γ )x² + ( αβ+βγ+αγ )x - αβγ
x³ - (20)x² + (124)x - 240
-> x³ - 20x² + 124x -240 =0
Hence, the cubic polynomial is x³ - 20x² + 124x -240.
Hope it helps ..........
Your answer is here....
Given zeroes are :- 6, 10, and 4.
Sum of the zeroes = α+β+γ
= 6 + 10 + 4 = 20
Sum of the product of the zeroes taken two at a time = αβ+βγ+αγ
= 6 X 10 + 10 X 4 + 4 X 6 = 60 + 40 + 24 = 124
Product of zeroes = αβγ
= 6 X 10 X 4 = 240.
Using the cubic formula,
x³ - ( α+β+γ )x² + ( αβ+βγ+αγ )x - αβγ
x³ - (20)x² + (124)x - 240
-> x³ - 20x² + 124x -240 =0
Hence, the cubic polynomial is x³ - 20x² + 124x -240.
Hope it helps ..........
Anonymous:
hiii
Answered by
10
Heya.
This is your answer ..
It is given that the zeroes are 6, 10, and 4.
Using the cubic formula,
-> x³ - ( α+β+γ )x² + ( αβ+βγ+αγ )x - αβγ
-> x³ - (6 + 10 + 4)x² + (6 X 10 + 10 X 4 + 4 X 6)x - 6 X 10 X 4
-> x³ - (20)x² + (124)x - 240
-> x³ - 20x² + 124x -240 =0
Hence, the required cubic polynomial is x³ - 20x² + 124x -240.
Hope I helped You..
This is your answer ..
It is given that the zeroes are 6, 10, and 4.
Using the cubic formula,
-> x³ - ( α+β+γ )x² + ( αβ+βγ+αγ )x - αβγ
-> x³ - (6 + 10 + 4)x² + (6 X 10 + 10 X 4 + 4 X 6)x - 6 X 10 X 4
-> x³ - (20)x² + (124)x - 240
-> x³ - 20x² + 124x -240 =0
Hence, the required cubic polynomial is x³ - 20x² + 124x -240.
Hope I helped You..
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