write roaster form of A={x:x3=x,x belongs to R}
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Given: The set A = { x : x³ = x , x belongs to R}
To find: The set in roaster form.
Solution:
- Now we have given the set in set builder form as:
A ={ x : x³ = x , x belongs to R}
- The condition is x³ = x.
- Putting x = 1, we get;
1³ = 1
True for x = 1
Putting x = -1, we get;
(-1)³ = -1
-1 = -1
True for x = -1
Putting x = 0, we get;
0³ = 0
0 = 0
True for x = 0
So the elements are: (1,1) , (-1,-1) and (0,0).
Answer:
So the set in roaster form is A = { (1,1) , (-1,-1) , (0,0) }
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