Question

Write Roman numerals CDXLIX in Arabic numerals
(a) 569
(b)
449
(c) 549
(d) 469​

Answer 1

Answer:

Given

m−5

2m

2

−3m+10

Now (2m

2

−3m+10) can be written after dividing by (m−5) as

(2m

2

−3m+10)=((2m+7)×(m−5))+45

so 45 is remainder and (2m+7) is dividend.

Answer 2

Answer:

1 = I

2 = Ii

3 = III

4 = IV

5 = V

6 = VI

7 = VII

8 = VIII

9 = IX

10 = X

11 = XI

12 = XII

13 = XIII

14 = XIV

15 = XV

16 = XVI

17 = XVII

18 = XVIII

19 = XIX

20 = XX

21 = XXI

22 = XXII

23 = XXIII

24 = XXIV

25 = XXV

26 = XXVI

27 = XXVII

28 = XXVIII

29 = XXIX

30 = XXX

31 = XXXI

32 = XXXII

33 = XXXIII

34 = XXXIV

35 = XXXV

36 = XXXVI

37 = XXXVII

38 = XXXVIII

39 = XXXIX

40 = XL

41 = XLI

42 = XLII

43 = XLIII

44 = XLIV

45 = XLV

46 = XLVI

47 = XLVII

48 = XLVIII

49 = XLIX

50 = L

51 = LI

52 = LII

53 = LIII

54 = LIV

55 = LV

56 = LVI

57 = LVII

58 = LVIII

59 = LIX

60 = LX

61 = LXI

62 = LXII

63 = LXIII

64 = LXIV

65 = LXV

66 = LXVI

67 = LXVII

68 = LXVIII

69 = LXIX

70 = LXX

71 = LXXI

72 = LXXII

73 = LXXIII

74 = LXXIV

75 = LXXV

76 = LXXVI

77 = LXXVII

78 = LXXVIII

79 = LXXIX

80 = LXXX

81 = LXXXI

82 = LXXXII

83 = LXXXIII

84 = LXXXIV

85 = LXXXV

86 = LXXXVI

87 = LXXXVII

88 = LXXXVIII

89 = LXXXIX

90 = XC

91 = XCI

92 = XCII

93 = XCIII

94 = XCIV

95 = XCV

96 = XCVI

97 = XCVII

98 = XCVIII

99 = XCIX

100 = C

101 = CI

102 = CII

103 = CIII

104 = CIV

105 = CV

106 = CVI

107 = CVII

108 = CVIII

109 = CIX

110 = CX

111 = CXI

112 = CXII

113 = CXIII

114 = CXIV

115 = CXV

116 = CXVI

117 = CXVII

118 = CXVIII

119 = CXIX

120 = CXX

121 = CXXI

122 = CXXII

123 = CXXIII

124 = CXXIV

125 = CXXV

126 = CXXVI

127 = CXXVII

128 = CXXVIII

129 = CXXIX

130 = CXXX

131 = CXXXI

132 = CXXXII

133 = CXXXIII