Question

Write s Pythagorean triplet whose one number is 6​

Answer 1

Answer:

HOPE IT HELPS ! PLZ MARK AS BRAINLIEST.........

Step-by-step explanation:

Pythagorean triplets

2m,m²-1,m²+1 forms a Pythagorean triplet.

Let 2m=6

m=6/2

m=3

m²-1=3²-1

=9-1

=8

m²+1=3²+1

=9+1

=10

Therefore the triplets are 6,8 and 10.

Answer 2

The required Pythagorean triplet

$2n,\: n { }^{2} + 1,n {}^{2}, - 1 \\ \\ Given \: one \: member = 6 \\ \\ 2n = 6 \\ n = \frac{6}{2} \\ \\ n = 3 \\ \\ n {}^{2} + 1 = 3 {}^{2} + 1 \\ \\ = 9 + 1 \\ = 10 \\ \\ n {}^{2} - 1 = 3 {}^{2} - 1 \\ \\ = 9 - 1 \\ \\ = 8 \\ \\ The \: required \: pythagorean \: triplet = 6,8,10.</p><p></p><p>$