Question

write separately what are the values a,x and y can take if a^x=a^y=x-y
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Answer 1

Answer:

x=y={any positive real number}   a=0

Step-by-step explanation:

$a^{x}=a^{y}=x-y\\ a^{x}=a^{y}\\x=y\\\\So,x-y=0\\a^{x}=a^{y}=0\\\\a=0$