Question

Write sin in terms of sec?

Answer 1

Plz see the attachment below-

Answer 2

We know that ,
 sin²x + cos²x = 1
⇒ sin²x = 1-cos²x
⇒ sinx = √(1-cos²x)
$sinx= \sqrt{1- \frac{1}{ sec^{2}x } } \\ sinx= \sqrt{ \frac{ sec^{2}x -1}{ sex^{2}x } }$
$sinx = \frac{ \sqrt{ sec^{2}x-1 } }{secx}$