Write smallest 3-digit number which is exathed divisible by 69.
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Smallest 3-digit number = 100
Number to be divisible by 69.
So,
69 )100( 1
69
31
So, we can see that 100 when divided by 69 gives quotient as 1 and remainder as 31.
So, (69 × 1) < the required number by 31.
Then, 69 × 2 = 138.
As we can see that 138 is greater than 100 by 38 which is closer to 31, so the required number is 138.
Hence, the required number is 138.
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