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Given :- ( a + b + c ) = 7 ....... (i)
( ab + bc + ac ) = 20 ...... (ii)
squaring both sides of eqⁿ i
( a + b + c )² = 7²
=> a² + b² + c² + 2ab + 2bc + 2ac = 49
=> a² + b² + c² + 2 ( ab + bc + ac ) = 49
=> a² + b² + c² + 2 ( 20 ) = 49 .... from ii
=> a² + b² + c² + 40 = 49
=> a² + b² + c² = 49 - 40
=> a² + b² + c² = 9
hope it helps..... !!!!
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