Math, asked by akshat8580, 8 months ago

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Answered by angelruhi
2

Given :- ( a + b + c ) = 7 ....... (i)

( ab + bc + ac ) = 20 ...... (ii)

squaring both sides of eqⁿ i

( a + b + c )² = 7²

=> a² + b² + c² + 2ab + 2bc + 2ac = 49

=> a² + b² + c² + 2 ( ab + bc + ac ) = 49

=> a² + b² + c² + 2 ( 20 ) = 49 .... from ii

=> a² + b² + c² + 40 = 49

=> a² + b² + c² = 49 - 40

=> a² + b² + c² = 9

hope it helps..... !!!!

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Answered by RajputAdarshsingh
1

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